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Engineering Professional Practice: Sample Case and a solution
Engineering Professional Practice: Sample Case and a solution Case: A client came to a designer’s and asked to design a multistoried building. The soil type is found not suitable for that type of structure. The designer hesitated to design a building. The revealed his/her intention as that he/she actually is not going to build that structure but he/she wanted to collect fund from outside sources on behalf of that design and ...
Case Studies of Engineering Professional Practice for Bachelors of Engineering
Case studies based on Codes of Ethics, Tort, Liability and Negligence in Professional Engineering Er Satyaman Shrestha was working as a Project Engineer in a road construction project in Chitwan. Er Ramesh Thapa, close friend of Satyaman was also working as a site engineer in the same project for a construction company. Construction work was in full swing.
Faith of an Engineer – a tale of engineering
The oath of an engineer in his profession, this is a master piece of the work. I am an ENGINEER. In my profession I take deep pride, but without vainglory; to it owe solemn obligations that I am eager to fulfill. As an Engineer, I will participate in none but honest enterprise. To him that he has engaged my service, as employer or client, I will give the utmost of performance and ...
Graphics Project : Bar Diagram [A Project work in Computer Graphics]
This was a Computer Graphics Project named Bar Diagram required in the coursework. [A Project work in Computer Graphics] #include #include #include #include #include #include /*FUNCTION FOR READING DATA FROM USER*/ void input(float ,float,float,float,float,float); /*FUNCTION FOR DRAWING BAR DIAGRAM*/ void bar1 (float); void bar2 (float); void bar3 (float); void bar4 (float); void bar5 (float); void bar6 (float); /* MAIN PROGRAM */ void main() { int gd=DETECT,gm; initgraph(&gd,&gm,”c:\\tc\\bgi”); float sub1,sub2,sub3,sub4,sub5,sub6; setbkcolor(9); setcolor(BLUE); settextstyle(3,0,2); outtextxy(getmaxx()/2-130,0,”TRIBHUWAN UNIVERSITY”); settextstyle(3,0,2); outtextxy(getmaxx()/2-145,30,”INSTITUTE OF ENGINEERING”); settextstyle(3,0,3); outtextxy(getmaxx()/2-155,60,”WESTERN REGION CAMPUS”); settextstyle(3,0,1); outtextxy(getmaxx()/2-135,92,”LAMACHAUR-16,POKHARA”); settextstyle(3,0,2); outtextxy(getmaxy()/2+50,getmaxy()/2,”A”); settextstyle(3,0,2); outtextxy(getmaxy()/2+15,260,”PROJECT”); settextstyle(3,0,2); outtextxy(getmaxy()/2+40,getmaxy()/2+40,”ON”); settextstyle(3,0,1); outtextxy(getmaxy()/2-50,300,”COMPUTER GRAPHICS”); outtextxy(getmaxx()-600,getmaxy()-140,”BY”); outtextxy(getmaxx()-600,getmaxy()-110,”Archana Shrestha”); outtextxy(getmaxx()-600,getmaxy()-80,”402/BEX/062″); delay(2500); cleardevice(); settextstyle(7,0,3); outtextxy(getmaxx()/2-250,getmaxy()/2,”PROGRAM TO DRAW A BAR DIAGRAM”); delay(1500); input(sub1,sub2,sub3,sub4,sub5,sub6); getch(); } /*END OF MAIN PROGRAM*/ /*FUNCTION FOR READING DATA FROM USER */ void input(float ...
Write an assembly program to READ YOUR NAME AND DISPLAY IT IN NEWLINE
Write an assembly program to READ YOUR NAME AND DISPLAY IT IN NEWLINE title read and display name dosseg .model small .stack 100H .code main proc mov ax, @data ; initialize ds register mov ds, ax mov ah, 09h ; display message1 mov dx, offset msg1 int 21h mov ah, 0ah ; read string mov dx, offset string int 21h mov alt, 09h ; your name is mov dx, offset msg2 int 21h mov ah, 09h ; string output mov dx, offset string int 21h mov ax, 4C00H ; return to ...
Write an assembly program to REVERSE THE GIVEN DIGITS
Write an assembly program to REVERSE THE GIVEN DIGITS title to reverse the given digits dosseg .model small .stack 100H .code main proc mov ax, @data ; initialize ds register mov ds, ax mov ax, value1 ; move number to ax mov cx, 0000h ; remainder r = 0 mov bx, 0010h ; for multiplication by 10h BACK: mov dx, 0000h ; clear upper 16-bits div bx ; divide the number ie dx= remainder, ax = quotient push ax ; push remainder and quotient ...
Write an assembly program to COPY A BLOCK OF DATA FROM ONE MEMORY TO ANOTHER
Write an assembly program to COPY A BLOCK OF DATA FROM ONE MEMORY TO ANOTHER title copy a block of data from one memory to another dosseg .model small .stack 100H .code main proc mov ax, @data ; initialize ds register mov ds, ax mov SI, offset array1 ; source index mov di, offset array2 ; destination index mov cx, 06H ; for 6 data ie cx is implicit counter BACK: mov al, [SI] mov [di], al ; move [di], [si] inc si inc di loop ...
Hardware Concept in Computer Graphics- Mouse and Pointing Devices
Mouse play a very important role in development of Computer Graphics and to implement graphics in the computer system. Mouse is a pointing input device that points out item(s) by cursor. The cursor can be move from one position to another, this movement of cursor is due to the movement of mouse in the plane surface. The movement of mouse occurs only in two directions- vertical and horizontal.
Write an assembly language program (Intel 8086) to READ A STRING, CONVERT IT INTO UPPER CASE AND FINALLY DISPLAY THE CONVERTED STRING
Write an assembly language program (Intel 8086) to READ A STRING, CONVERT IT INTO UPPER CASE AND FINALLY DISPLAY THE CONVERTED STRING title ALP to read a string, convert it into upper case and display the converted string dosseg .model small .stack 100H .code main proc far mov ax, @data ; initialize ds register mov ds, ax   mov ah, 0ah ; read string lea ax, param int 21h   mov bx, 00 ; convert to upper string mov cx, act_len L2:          mov ah, ...
To evaluate ordinary differential equations by RK-4 (Classical) Method
Evaluating ordinary differential equations by RK-4 or classical method both order first and second //To compute ordinary differential equations by RK-4 or classical method for order first #include #include #include void main() { cout<<”\t first order R-K 4th Classical Method\t”< double h,n,m1,i,m2,m3,m4,x[100],y[100]; cout<<”Number of intervals “; cin>>n; cout< cout<<”Enter the value of h”<<<”h = “; cin>>h; cout<<”Enter the value of x0″<<<”x0 = “; cin>>x[0]; cout<<”Enter the value of y0″<<<”y0 = “; cin>>y[0]; cout< for(i=0;i<=n;i++) { x[i+1]=x[i]+h; m1=h*.5*(1+x[i])*(y[i]*y[i]); m2=h*.5*(1+(x[i]+.5*h))*(y[i]+m1*.5*h)*(y[i]+m1*.5*h); m3=h*.5*(1+(x[i]+.5*h))*(y[i]+m2*.5*h)*(y[i]+m2*.5*h); m4=h*.5*(1+(x[i]+h))*(y[i]+m3*h)*(y[i]+m3*h); y[i+1]=y[i]+(m1+2.0*m2+2.0*m3+m4)/6; cout<<”x”<<<”= “<< cout<<”y”<<<”= “<< cout< } getch(); } // To compute ordinary differential equations by RK-4 or classical method for order second #include #include #include void ...
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